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A container has 60 liters of a solution that is 40% acid. If 15 liters of the so

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Question: A container has 60 liters of a solution that is 40% acid. If 15 liters of the solution is removed and replaced with water, what is the new percentage of acid?

Options:

  1. 30%
  2. 35%
  3. 40%
  4. 25%

Correct Answer: 35%

Solution: 

Acid removed = 40% of 15L = 6L. Remaining acid = 24L, new total = 60L, new acid % = (24/60)*100 = 40%.

A container has 60 liters of a solution that is 40% acid. If 15 liters of the so

Practice Questions

Q1
A container has 60 liters of a solution that is 40% acid. If 15 liters of the solution is removed and replaced with water, what is the new percentage of acid?
  1. 30%
  2. 35%
  3. 40%
  4. 25%

Questions & Step-by-Step Solutions

A container has 60 liters of a solution that is 40% acid. If 15 liters of the solution is removed and replaced with water, what is the new percentage of acid?
  • Step 1: Start with a container that has 60 liters of a solution that is 40% acid.
  • Step 2: Calculate how much acid is in the original solution. 40% of 60 liters is 24 liters of acid.
  • Step 3: Remove 15 liters of the solution from the container.
  • Step 4: Calculate how much acid is in the 15 liters that was removed. 40% of 15 liters is 6 liters of acid.
  • Step 5: Subtract the acid removed from the original amount of acid. 24 liters - 6 liters = 18 liters of acid remaining.
  • Step 6: The total volume of the solution is still 60 liters because we replace the 15 liters removed with water.
  • Step 7: Calculate the new percentage of acid in the solution. Divide the remaining acid (18 liters) by the total volume (60 liters) and multiply by 100.
  • Step 8: The new percentage of acid is (18/60) * 100 = 30%.
  • Concentration and Dilution – Understanding how the concentration of a solution changes when a portion is removed and replaced with a solvent.
  • Percentage Calculation – Calculating the percentage of a component in a solution after changes in volume and composition.
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