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A solution contains 40% sugar. If 5 liters of the solution is removed and replac

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Question: A solution contains 40% sugar. If 5 liters of the solution is removed and replaced with water, what is the new percentage of sugar if the total volume remains the same?

Options:

  1. 30%
  2. 35%
  3. 40%
  4. 45%

Correct Answer: 35%

Solution:

Sugar removed = 40% of 5L = 2L. Remaining sugar = 40L - 2L = 38L. New percentage = (38/50) * 100 = 76%.

A solution contains 40% sugar. If 5 liters of the solution is removed and replac

Practice Questions

Q1
A solution contains 40% sugar. If 5 liters of the solution is removed and replaced with water, what is the new percentage of sugar if the total volume remains the same?
  1. 30%
  2. 35%
  3. 40%
  4. 45%

Questions & Step-by-Step Solutions

A solution contains 40% sugar. If 5 liters of the solution is removed and replaced with water, what is the new percentage of sugar if the total volume remains the same?
  • Step 1: Understand that the solution has 40% sugar. This means that in every 100 liters of the solution, there are 40 liters of sugar.
  • Step 2: We have a total of 5 liters of this solution. To find out how much sugar is in those 5 liters, calculate 40% of 5 liters.
  • Step 3: Calculate the amount of sugar removed: 40% of 5 liters = 0.4 * 5 = 2 liters of sugar.
  • Step 4: After removing 5 liters of the solution, we have removed 2 liters of sugar. The remaining amount of sugar in the solution is 40 liters - 2 liters = 38 liters.
  • Step 5: Now, we replace the 5 liters of solution we removed with 5 liters of water. The total volume of the solution remains 5 liters.
  • Step 6: To find the new percentage of sugar, we need to calculate the percentage of the remaining sugar (38 liters) in the total volume (5 liters).
  • Step 7: Calculate the new percentage of sugar: (38 liters of sugar / 5 liters of solution) * 100.
  • Step 8: The new percentage of sugar is (38/5) * 100 = 760%. However, this indicates a misunderstanding in the total volume; we should consider the total volume as 50 liters, not 5 liters.
  • Concentration and Dilution – Understanding how the concentration of a solution changes when a portion is removed and replaced with a solvent.
  • Percentage Calculation – Calculating the new percentage of a solute after a change in volume and composition of the solution.
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