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In a mixture of two liquids A and B, the ratio of A to B is 3:2. If the total vo

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Question: In a mixture of two liquids A and B, the ratio of A to B is 3:2. If the total volume of the mixture is 50 liters, how much of liquid A is there?

Options:

  1. 20 liters
  2. 25 liters
  3. 30 liters
  4. 35 liters

Correct Answer: 30 liters

Solution: 

Let the volumes of A and B be 3x and 2x respectively. 3x + 2x = 50, x = 10. Therefore, A = 3 * 10 = 30 liters.

In a mixture of two liquids A and B, the ratio of A to B is 3:2. If the total vo

Practice Questions

Q1
In a mixture of two liquids A and B, the ratio of A to B is 3:2. If the total volume of the mixture is 50 liters, how much of liquid A is there?
  1. 20 liters
  2. 25 liters
  3. 30 liters
  4. 35 liters

Questions & Step-by-Step Solutions

In a mixture of two liquids A and B, the ratio of A to B is 3:2. If the total volume of the mixture is 50 liters, how much of liquid A is there?
  • Step 1: Understand the ratio of liquids A and B, which is 3:2. This means for every 3 parts of A, there are 2 parts of B.
  • Step 2: Let 'x' be a common multiplier. Then, the volume of liquid A can be represented as 3x and the volume of liquid B as 2x.
  • Step 3: Write an equation for the total volume of the mixture. Since the total volume is 50 liters, we can write: 3x + 2x = 50.
  • Step 4: Combine the terms on the left side of the equation: 5x = 50.
  • Step 5: Solve for 'x' by dividing both sides of the equation by 5: x = 10.
  • Step 6: Now, calculate the volume of liquid A by substituting 'x' back into the expression for A: A = 3 * x = 3 * 10.
  • Step 7: Finally, calculate the result: A = 30 liters.
  • Ratios – Understanding and applying the concept of ratios to determine the parts of a whole.
  • Algebraic Equations – Setting up and solving equations based on given relationships and total quantities.
  • Mixture Problems – Applying knowledge of mixtures to find individual components based on their ratios.
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