Question: A mixture contains 30% alcohol and 70% water. If 20 liters of the mixture is taken out and replaced with water, what is the new percentage of alcohol in the mixture?
Options:
Correct Answer: 28%
Solution:
Initial alcohol = 30% of 20L = 6L. Remaining alcohol = 30L - 6L = 24L. New mixture = 24L + 20L = 44L. New percentage of alcohol = (24/44) * 100 = 54.55%.