What is the standard entropy change (ΔS°) for the reaction: 2SO2(g) + O2(g) → 2S

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Question: What is the standard entropy change (ΔS°) for the reaction: 2SO2(g) + O2(g) → 2SO3(g)?

Options:

Correct Answer: Decreases

Solution:

The reaction decreases the number of gas molecules from 3 to 2, leading to a decrease in entropy.

What is the standard entropy change (ΔS°) for the reaction: 2SO2(g) + O2(g) → 2SO3(g)?

What is the standard entropy change (ΔS°) for the reaction: 2SO2(g) + O2(g) → 2SO3(g)?

Correct Answer: ΔS° < 0

Step 1: Identify the reactants and products in the reaction: 2SO2(g) + O2(g) → 2SO3(g).
Step 2: Count the number of gas molecules on the reactant side: 2 SO2 + 1 O2 = 3 gas molecules.
Step 3: Count the number of gas molecules on the product side: 2 SO3 = 2 gas molecules.
Step 4: Compare the number of gas molecules: The number of gas molecules decreases from 3 to 2.
Step 5: Understand that a decrease in the number of gas molecules usually leads to a decrease in entropy (ΔS°).
Step 6: Conclude that the standard entropy change (ΔS°) for this reaction is negative.

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