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What is the standard entropy change (ΔS°) for the reaction: 2SO2(g) + O2(g) → 2S
What is the standard entropy change (ΔS°) for the reaction: 2SO2(g) + O2(g) → 2SO3(g)?
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Q1
What is the standard entropy change (ΔS°) for the reaction: 2SO2(g) + O2(g) → 2SO3(g)?
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The reaction decreases the number of gas molecules from 3 to 2, leading to a decrease in entropy.
Questions & Step-by-step Solutions
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Q
Q: What is the standard entropy change (ΔS°) for the reaction: 2SO2(g) + O2(g) → 2SO3(g)?
Solution:
The reaction decreases the number of gas molecules from 3 to 2, leading to a decrease in entropy.
Steps: 6
Show Steps
Step 1: Identify the reactants and products in the reaction: 2SO2(g) + O2(g) → 2SO3(g).
Step 2: Count the number of gas molecules on the reactant side: 2 SO2 + 1 O2 = 3 gas molecules.
Step 3: Count the number of gas molecules on the product side: 2 SO3 = 2 gas molecules.
Step 4: Compare the number of gas molecules: The number of gas molecules decreases from 3 to 2.
Step 5: Understand that a decrease in the number of gas molecules usually leads to a decrease in entropy (ΔS°).
Step 6: Conclude that the standard entropy change (ΔS°) for this reaction is negative.
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