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What is the enthalpy change for the reaction: 2H2(g) + O2(g) β†’ 2H2O(g)?

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Question: What is the enthalpy change for the reaction: 2H2(g) + O2(g) β†’ 2H2O(g)?

Options:

  1. It is positive.
  2. It is negative.
  3. It is zero.
  4. It is dependent on temperature.

Correct Answer: It is negative.

Solution: 

The formation of water from hydrogen and oxygen is an exothermic reaction, thus the enthalpy change is negative.

What is the enthalpy change for the reaction: 2H2(g) + O2(g) β†’ 2H2O(g)?

Practice Questions

Q1
What is the enthalpy change for the reaction: 2H2(g) + O2(g) β†’ 2H2O(g)?
  1. It is positive.
  2. It is negative.
  3. It is zero.
  4. It is dependent on temperature.

Questions & Step-by-Step Solutions

What is the enthalpy change for the reaction: 2H2(g) + O2(g) β†’ 2H2O(g)?
Correct Answer: Negative enthalpy change
  • Step 1: Identify the reactants in the reaction, which are hydrogen gas (H2) and oxygen gas (O2).
  • Step 2: Identify the product of the reaction, which is water in gas form (H2O).
  • Step 3: Understand that the reaction combines hydrogen and oxygen to form water.
  • Step 4: Recognize that this reaction releases energy, meaning it is exothermic.
  • Step 5: Conclude that because the reaction releases energy, the enthalpy change (Ξ”H) is negative.
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