Question: What is the heat required to raise the temperature of 3 kg of aluminum from 25°C to 75°C? (Specific heat of aluminum = 900 J/kg°C)
Options:
Correct Answer: 135000 J
Solution:
Using Q = mcΔT, Q = 3 kg * 900 J/kg°C * (75°C - 25°C) = 3 * 900 * 50 = 135000 J.