Question: What is the total capacitance of two capacitors of 4 µF and 6 µF connected in series?
Options:
Correct Answer: 2.4 µF
Solution:
Total capacitance C_total = 1 / (1/C₁ + 1/C₂) = 1 / (1/4 + 1/6) = 2.4 µF.