Question: What is the equivalent resistance of three resistors of 4 Ω, 6 Ω, and 12 Ω connected in series?
Options:
Correct Answer: 22 Ω
Solution:
Equivalent resistance R_eq = R₁ + R₂ + R₃ = 4 Ω + 6 Ω + 12 Ω = 22 Ω.