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If the electric field between two parallel plates is 2000 N/C, what is the poten

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Question: If the electric field between two parallel plates is 2000 N/C, what is the potential difference between the plates if they are 0.05 m apart?

Options:

  1. 100 V
  2. 200 V
  3. 300 V
  4. 400 V

Correct Answer: 200 V

Solution: 

Potential difference V = E * d = 2000 N/C * 0.05 m = 100 V.

If the electric field between two parallel plates is 2000 N/C, what is the poten

Practice Questions

Q1
If the electric field between two parallel plates is 2000 N/C, what is the potential difference between the plates if they are 0.05 m apart?
  1. 100 V
  2. 200 V
  3. 300 V
  4. 400 V

Questions & Step-by-Step Solutions

If the electric field between two parallel plates is 2000 N/C, what is the potential difference between the plates if they are 0.05 m apart?
  • Step 1: Identify the electric field (E) between the plates, which is given as 2000 N/C.
  • Step 2: Identify the distance (d) between the plates, which is given as 0.05 m.
  • Step 3: Use the formula for potential difference (V), which is V = E * d.
  • Step 4: Substitute the values into the formula: V = 2000 N/C * 0.05 m.
  • Step 5: Calculate the result: V = 100 V.
  • Electric Field and Potential Difference – The relationship between electric field (E), potential difference (V), and distance (d) is given by the formula V = E * d.
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