Question: What is the capacitance of a parallel plate capacitor with an area of 2 m² and a separation of 0.01 m filled with a dielectric of relative permittivity 5?

Options:

1. 0.88 µF
2. 1.77 µF
3. 2.65 µF
4. 3.54 µF

Correct Answer: 1.77 µF

Solution:

Capacitance C = (ε₀ * ε_r * A) / d = (8.85 x 10^-12 F/m * 5 * 2 m²) / 0.01 m = 8.85 x 10^-11 F = 1.77 µF.