If a capacitor has a capacitance of 2μF and is charged to 10V, what is the charg

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Question: If a capacitor has a capacitance of 2μF and is charged to 10V, what is the charge stored in the capacitor?

Options:

Correct Answer: 20μC

Solution:

The charge stored in the capacitor is given by Q = C*V = 2μF * 10V = 20μC.

If a capacitor has a capacitance of 2μF and is charged to 10V, what is the charge stored in the capacitor?

If a capacitor has a capacitance of 2μF and is charged to 10V, what is the charge stored in the capacitor?

Step 1: Identify the values given in the problem. The capacitance (C) is 2 microfarads (μF) and the voltage (V) is 10 volts (V).
Step 2: Convert the capacitance from microfarads to farads. 2μF is equal to 2 x 10^-6 F.
Step 3: Use the formula for charge (Q) stored in a capacitor, which is Q = C * V.
Step 4: Substitute the values into the formula: Q = (2 x 10^-6 F) * (10 V).
Step 5: Calculate the charge: Q = 20 x 10^-6 C, which is equal to 20 microcoulombs (μC).

Capacitance and Charge Relationship – The relationship between capacitance (C), voltage (V), and charge (Q) is defined by the formula Q = C * V, where Q is the charge in coulombs, C is the capacitance in farads, and V is the voltage in volts.