Question: What is the equivalent capacitance of two capacitors, 2 µF and 3 µF, connected in series?
Options:
Correct Answer: 1.2 µF
Solution:
For capacitors in series, 1/C_eq = 1/C1 + 1/C2. Thus, 1/C_eq = 1/2 + 1/3 = 5/6. Therefore, C_eq = 6/5 = 1.2 µF.