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In a series circuit with a 12 V battery and two resistors of 4 Ω and 6 Ω, what i

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Question: In a series circuit with a 12 V battery and two resistors of 4 Ω and 6 Ω, what is the voltage across the 4 Ω resistor?

Options:

  1. 4.8 V
  2. 6 V
  3. 8 V
  4. 3.6 V

Correct Answer: 4.8 V

Solution: 

Total resistance R = 4 Ω + 6 Ω = 10 Ω. Current I = V/R = 12 V / 10 Ω = 1.2 A. Voltage across 4 Ω = I * R = 1.2 A * 4 Ω = 4.8 V.

In a series circuit with a 12 V battery and two resistors of 4 Ω and 6 Ω, what i

Practice Questions

Q1
In a series circuit with a 12 V battery and two resistors of 4 Ω and 6 Ω, what is the voltage across the 4 Ω resistor?
  1. 4.8 V
  2. 6 V
  3. 8 V
  4. 3.6 V

Questions & Step-by-Step Solutions

In a series circuit with a 12 V battery and two resistors of 4 Ω and 6 Ω, what is the voltage across the 4 Ω resistor?
  • Ohm's Law – The relationship between voltage (V), current (I), and resistance (R) in an electrical circuit, expressed as V = I * R.
  • Series Circuit – A circuit configuration where components are connected end-to-end, resulting in the same current flowing through each component.
  • Voltage Division – The principle that in a series circuit, the total voltage is divided among the resistors in proportion to their resistances.
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