Question: What is the electric potential energy of a charge of +2 µC placed in an electric field of 500 N/C at a distance of 0.1 m?

Options:

1. 0.1 mJ
2. 0.2 mJ
3. 0.3 mJ
4. 0.4 mJ

Correct Answer: 0.2 mJ

Solution:

Electric potential energy U = q * E * d = (2 x 10^-6 C) * (500 N/C) * (0.1 m) = 0.1 mJ.