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In a circuit with a 24V battery and two resistors in series (4Ω and 8Ω), what is

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Question: In a circuit with a 24V battery and two resistors in series (4Ω and 8Ω), what is the voltage drop across the 8Ω resistor?

Options:

  1. 8V
  2. 12V
  3. 16V
  4. 20V

Correct Answer: 12V

Solution: 

Total resistance R = 4Ω + 8Ω = 12Ω. Current I = V/R = 24V / 12Ω = 2A. Voltage drop across 8Ω = I * R = 2A * 8Ω = 16V.

In a circuit with a 24V battery and two resistors in series (4Ω and 8Ω), what is

Practice Questions

Q1
In a circuit with a 24V battery and two resistors in series (4Ω and 8Ω), what is the voltage drop across the 8Ω resistor?
  1. 8V
  2. 12V
  3. 16V
  4. 20V

Questions & Step-by-Step Solutions

In a circuit with a 24V battery and two resistors in series (4Ω and 8Ω), what is the voltage drop across the 8Ω resistor?
  • Ohm's Law – The relationship between voltage (V), current (I), and resistance (R) in an electrical circuit, expressed as V = I * R.
  • Series Circuits – In a series circuit, the total resistance is the sum of individual resistances, and the same current flows through all components.
  • Voltage Division – In a series circuit, the voltage drop across a resistor is proportional to its resistance relative to the total resistance.
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