What is the potential difference across a capacitor of 8 µF if it stores a charg

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Question: What is the potential difference across a capacitor of 8 µF if it stores a charge of 16 µC?

Options:

Correct Answer: 2V

Solution:

Using the formula Q = C * V, we have V = Q / C = 16 x 10^-6 C / 8 x 10^-6 F = 2V.

What is the potential difference across a capacitor of 8 µF if it stores a charge of 16 µC?

What is the potential difference across a capacitor of 8 µF if it stores a charge of 16 µC?

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