Question: What is the electric field strength between two parallel plates separated by 0.1 m with a potential difference of 100 V?

Options:

1. 1000 N/C
2. 500 N/C
3. 100 N/C
4. 2000 N/C

Correct Answer: 1000 N/C

Solution:

The electric field (E) is given by E = V/d. Here, E = 100V / 0.1m = 1000 N/C.