In a simple series circuit with a 12V battery and two resistors (4Ω and 8Ω), wha

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Question: In a simple series circuit with a 12V battery and two resistors (4Ω and 8Ω), what is the total current flowing through the circuit?

Options:

Correct Answer: 2A

Solution:

Total resistance R_total = R1 + R2 = 4Ω + 8Ω = 12Ω. Using Ohm\'s Law, I = V / R_total = 12V / 12Ω = 1A.

In a simple series circuit with a 12V battery and two resistors (4Ω and 8Ω), what is the total current flowing through the circuit?

In a simple series circuit with a 12V battery and two resistors (4Ω and 8Ω), what is the total current flowing through the circuit?

Step 1: Identify the components in the circuit. We have a 12V battery and two resistors: one is 4Ω and the other is 8Ω.
Step 2: Calculate the total resistance in the circuit. Since the resistors are in series, we add their resistances together: R_total = R1 + R2 = 4Ω + 8Ω.
Step 3: Perform the addition: R_total = 4Ω + 8Ω = 12Ω.
Step 4: Use Ohm's Law to find the current. Ohm's Law states that I = V / R, where I is the current, V is the voltage, and R is the resistance.
Step 5: Substitute the values into Ohm's Law: I = 12V / 12Ω.
Step 6: Perform the division: I = 1A.
Step 7: Conclude that the total current flowing through the circuit is 1A.

Ohm's Law – The relationship between voltage, current, and resistance in an electrical circuit, expressed as I = V / R.
Series Circuit – A circuit configuration where components are connected end-to-end, resulting in the same current flowing through each component.
Total Resistance in Series – In a series circuit, the total resistance is the sum of the individual resistances.