Question: What is the electric field (E) at a distance of 2m from a point charge of 10μC?

Options:

1. 2250 N/C
2. 500 N/C
3. 4500 N/C
4. 1000 N/C

Correct Answer: 2250 N/C

Solution:

Using Coulomb\'s law, E = k * |Q| / r^2 = (8.99 x 10^9 N m²/C²) * (10 x 10^-6 C) / (2 m)^2 = 2247.5 N/C, approximately 2250 N/C.