A capacitor with a capacitance of 10μF is charged to a voltage of 5V. What is th

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Question: A capacitor with a capacitance of 10μF is charged to a voltage of 5V. What is the charge stored in the capacitor?

Options:

Correct Answer: 50μC

Solution:

The charge stored in a capacitor is given by Q = C * V = 10μF * 5V = 50μC.

A capacitor with a capacitance of 10μF is charged to a voltage of 5V. What is the charge stored in the capacitor?

A capacitor with a capacitance of 10μF is charged to a voltage of 5V. What is the charge stored in the capacitor?

Step 1: Identify the formula for charge stored in a capacitor, which is Q = C * V.
Step 2: Identify the values given in the question: capacitance (C) is 10μF and voltage (V) is 5V.
Step 3: Convert the capacitance from microfarads (μF) to farads (F) if necessary. 10μF = 10 * 10^-6 F = 0.00001 F.
Step 4: Substitute the values into the formula: Q = 10μF * 5V.
Step 5: Calculate the charge: Q = 10 * 10^-6 F * 5V = 50 * 10^-6 C.
Step 6: Convert the charge from coulombs (C) to microcoulombs (μC): 50 * 10^-6 C = 50μC.

Capacitance and Charge Relationship – The relationship between charge (Q), capacitance (C), and voltage (V) is defined by the formula Q = C * V, where Q is the charge in coulombs, C is the capacitance in farads, and V is the voltage in volts.