Question: What is the equivalent capacitance of two capacitors of 4 µF and 6 µF connected in series?

Options:

1. 2.4 µF
2. 10 µF
3. 1.5 µF
4. 3.6 µF

Correct Answer: 2.4 µF

Solution:

1/C_total = 1/C1 + 1/C2 = 1/4 µF + 1/6 µF = 1.2 µF, so C_total = 2.4 µF.