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In a circuit with a 24V power supply and two resistors of 8Ω and 4Ω in series, w

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Question: In a circuit with a 24V power supply and two resistors of 8Ω and 4Ω in series, what is the voltage drop across the 4Ω resistor?

Options:

  1. 4.8 V
  2. 8 V
  3. 12 V
  4. 16 V

Correct Answer: 12 V

Solution: 

Total resistance R = 8Ω + 4Ω = 12Ω. Current I = V/R = 24V / 12Ω = 2A. Voltage drop V_R = I * R = 2A * 4Ω = 8 V.

In a circuit with a 24V power supply and two resistors of 8Ω and 4Ω in series, w

Practice Questions

Q1
In a circuit with a 24V power supply and two resistors of 8Ω and 4Ω in series, what is the voltage drop across the 4Ω resistor?
  1. 4.8 V
  2. 8 V
  3. 12 V
  4. 16 V

Questions & Step-by-Step Solutions

In a circuit with a 24V power supply and two resistors of 8Ω and 4Ω in series, what is the voltage drop across the 4Ω resistor?
  • Ohm's Law – The relationship between voltage (V), current (I), and resistance (R) in an electrical circuit, expressed as V = I * R.
  • Series Circuits – In a series circuit, the total resistance is the sum of individual resistances, and the same current flows through all components.
  • Voltage Division – In a series circuit, the voltage drop across a resistor can be calculated using the current flowing through it and its resistance.
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