If a capacitor of 5 µF is charged to 12 V, what is the energy stored in the capa

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Question: If a capacitor of 5 µF is charged to 12 V, what is the energy stored in the capacitor?

Options:

Correct Answer: 0.36 mJ

Solution:

Energy stored U = 0.5 * C * V^2 = 0.5 * 5 x 10^-6 F * (12 V)^2 = 0.36 mJ.

If a capacitor of 5 µF is charged to 12 V, what is the energy stored in the capacitor?

If a capacitor of 5 µF is charged to 12 V, what is the energy stored in the capacitor?

Step 1: Identify the values given in the problem. We have a capacitor with a capacitance (C) of 5 microfarads (µF) and a voltage (V) of 12 volts (V).
Step 2: Convert the capacitance from microfarads to farads. 5 µF is equal to 5 x 10^-6 F.
Step 3: Write down the formula for the energy (U) stored in a capacitor: U = 0.5 * C * V^2.
Step 4: Substitute the values into the formula. U = 0.5 * (5 x 10^-6 F) * (12 V)^2.
Step 5: Calculate (12 V)^2, which is 144 V^2.
Step 6: Now substitute this value back into the equation: U = 0.5 * (5 x 10^-6 F) * 144 V^2.
Step 7: Multiply 0.5 by 5 x 10^-6 to get 2.5 x 10^-6.
Step 8: Now multiply 2.5 x 10^-6 by 144 to get 0.00036 joules.
Step 9: Convert joules to millijoules (mJ) by multiplying by 1000. 0.00036 joules is equal to 0.36 mJ.

Capacitance and Energy Storage – Understanding how capacitors store energy based on their capacitance and voltage.
Energy Formula for Capacitors – Application of the formula U = 0.5 * C * V^2 to calculate energy stored in a capacitor.