If a spring with a spring constant of 200 N/m is compressed by 0.5 m, what is th

₹0.0

Question: If a spring with a spring constant of 200 N/m is compressed by 0.5 m, what is the potential energy stored in the spring?

Options:

Correct Answer: 50 J

Solution:

Potential Energy = 0.5 × k × x² = 0.5 × 200 N/m × (0.5 m)² = 25 J.

If a spring with a spring constant of 200 N/m is compressed by 0.5 m, what is the potential energy stored in the spring?

If a spring with a spring constant of 200 N/m is compressed by 0.5 m, what is the potential energy stored in the spring?

Step 1: Identify the spring constant (k). In this case, k = 200 N/m.
Step 2: Identify the compression of the spring (x). Here, x = 0.5 m.
Step 3: Use the formula for potential energy stored in a spring: Potential Energy = 0.5 × k × x².
Step 4: Substitute the values into the formula: Potential Energy = 0.5 × 200 N/m × (0.5 m)².
Step 5: Calculate (0.5 m)², which equals 0.25 m².
Step 6: Multiply 200 N/m by 0.25 m², which equals 50 N·m.
Step 7: Multiply 50 N·m by 0.5, which equals 25 J.
Step 8: Conclude that the potential energy stored in the spring is 25 Joules.

Potential Energy in Springs – The potential energy stored in a spring is calculated using the formula PE = 0.5 × k × x², where k is the spring constant and x is the compression or extension of the spring.