A train moving at 72 km/h comes to a stop in 5 seconds. What is the train's dece

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Question: A train moving at 72 km/h comes to a stop in 5 seconds. What is the train\'s deceleration?

Options:

Correct Answer: 4 m/s²

Solution:

First convert speed to m/s: 72 km/h = 20 m/s. Deceleration = (final velocity - initial velocity) / time = (0 - 20) / 5 = -4 m/s².

A train moving at 72 km/h comes to a stop in 5 seconds. What is the train's deceleration?

A train moving at 72 km/h comes to a stop in 5 seconds. What is the train's deceleration?

Step 1: Convert the train's speed from kilometers per hour (km/h) to meters per second (m/s). Use the conversion factor: 1 km/h = 1/3.6 m/s.
Step 2: Calculate the speed in m/s: 72 km/h = 72 / 3.6 = 20 m/s.
Step 3: Identify the initial velocity (the speed of the train before stopping) which is 20 m/s.
Step 4: Identify the final velocity (the speed of the train after stopping) which is 0 m/s.
Step 5: Use the formula for deceleration: Deceleration = (final velocity - initial velocity) / time.
Step 6: Plug in the values: Deceleration = (0 m/s - 20 m/s) / 5 seconds.
Step 7: Calculate the deceleration: Deceleration = -20 m/s / 5 seconds = -4 m/s².

Unit Conversion – Converting speed from kilometers per hour to meters per second.
Deceleration Calculation – Using the formula for deceleration, which is the change in velocity over time.