A 4 kg object is moving at 6 m/s. If it collides with a wall and comes to a stop

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Question: A 4 kg object is moving at 6 m/s. If it collides with a wall and comes to a stop, what is the impulse experienced by the object?

Options:

Correct Answer: 24 Ns

Solution:

Impulse (J) = change in momentum = mass (m) × change in velocity (Δv) = 4 kg × (0 - 6 m/s) = -24 Ns.

A 4 kg object is moving at 6 m/s. If it collides with a wall and comes to a stop, what is the impulse experienced by the object?

A 4 kg object is moving at 6 m/s. If it collides with a wall and comes to a stop, what is the impulse experienced by the object?

Step 1: Identify the mass of the object. The mass (m) is given as 4 kg.
Step 2: Identify the initial velocity of the object. The initial velocity (v_initial) is given as 6 m/s.
Step 3: Determine the final velocity after the collision. Since the object comes to a stop, the final velocity (v_final) is 0 m/s.
Step 4: Calculate the change in velocity (Δv). This is done by subtracting the final velocity from the initial velocity: Δv = v_final - v_initial = 0 m/s - 6 m/s = -6 m/s.
Step 5: Use the impulse formula. Impulse (J) is equal to the mass multiplied by the change in velocity: J = m × Δv.
Step 6: Substitute the values into the formula: J = 4 kg × (-6 m/s).
Step 7: Calculate the impulse: J = -24 kg·m/s or -24 Ns.

Impulse – Impulse is the change in momentum of an object when a force is applied over a period of time.
Momentum – Momentum is the product of an object's mass and its velocity, and it is conserved in isolated systems.
Change in Velocity – The change in velocity is calculated as the final velocity minus the initial velocity.