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If a rotating object has a moment of inertia of 2 kg·m² and an angular accelerat

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Question: If a rotating object has a moment of inertia of 2 kg·m² and an angular acceleration of 3 rad/s², what is the torque applied?

Options:

  1. 6 N·m
  2. 5 N·m
  3. 3 N·m
  4. 2 N·m

Correct Answer: 6 N·m

Solution: 

Torque is calculated as τ = I * α, where I is the moment of inertia and α is the angular acceleration. Here, τ = 2 kg·m² * 3 rad/s² = 6 N·m.

If a rotating object has a moment of inertia of 2 kg·m² and an angular accelerat

Practice Questions

Q1
If a rotating object has a moment of inertia of 2 kg·m² and an angular acceleration of 3 rad/s², what is the torque applied?
  1. 6 N·m
  2. 5 N·m
  3. 3 N·m
  4. 2 N·m

Questions & Step-by-Step Solutions

If a rotating object has a moment of inertia of 2 kg·m² and an angular acceleration of 3 rad/s², what is the torque applied?
  • Step 1: Identify the formula for torque, which is τ = I * α.
  • Step 2: Understand that 'I' is the moment of inertia and 'α' is the angular acceleration.
  • Step 3: Substitute the given values into the formula: I = 2 kg·m² and α = 3 rad/s².
  • Step 4: Calculate the torque: τ = 2 kg·m² * 3 rad/s².
  • Step 5: Perform the multiplication: 2 * 3 = 6.
  • Step 6: Write the final answer: τ = 6 N·m.
  • Torque Calculation – Understanding the relationship between torque, moment of inertia, and angular acceleration using the formula τ = I * α.
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