Question: In a series circuit with two capacitors of capacitance 3 µF and 6 µF, what is the total capacitance?

Options:

1. 2 µF
2. 1 µF
3. 9 µF
4. 4 µF

Correct Answer: 2 µF

Solution:

Total capacitance in series is given by 1/C_total = 1/C1 + 1/C2. Thus, 1/C_total = 1/3 + 1/6 = 1/2, so C_total = 2 µF.