Question: What is the electric potential energy of a charge of +3 µC placed in an electric field of 2000 N/C at a distance of 0.5 m?

Options:

1. 3 J
2. 1.5 J
3. 0.3 J
4. 0.6 J

Correct Answer: 1.5 J

Solution:

Potential energy U = q * E * d = (3 x 10^-6 C) * (2000 N/C) * (0.5 m) = 3 J.