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In a parallel circuit with three resistors of 2Ω, 3Ω, and 6Ω, what is the total

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Question: In a parallel circuit with three resistors of 2Ω, 3Ω, and 6Ω, what is the total resistance?

Options:

  1. 1Ω
  2. 2Ω
  3. 3Ω
  4. 4Ω

Correct Answer: 1Ω

Solution: 

1/Rtotal = 1/R1 + 1/R2 + 1/R3 = 1/2 + 1/3 + 1/6 = 1Ω.

In a parallel circuit with three resistors of 2Ω, 3Ω, and 6Ω, what is the total

Practice Questions

Q1
In a parallel circuit with three resistors of 2Ω, 3Ω, and 6Ω, what is the total resistance?
  1. 1Ω
  2. 2Ω
  3. 3Ω
  4. 4Ω

Questions & Step-by-Step Solutions

In a parallel circuit with three resistors of 2Ω, 3Ω, and 6Ω, what is the total resistance?
  • Parallel Circuit Resistance – In a parallel circuit, the total resistance is found using the formula 1/Rtotal = 1/R1 + 1/R2 + 1/R3, where R1, R2, and R3 are the resistances of the individual resistors.
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