Using Kirchhoff's Voltage Law, if a loop has a 12V source and two resistors of 3

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What’s inside this PDF?

Question: Using Kirchhoff\'s Voltage Law, if a loop has a 12V source and two resistors of 3Ω and 4Ω, what is the voltage drop across the 3Ω resistor?

Options:

4.29V
5.14V
3.43V
6.0V

Correct Answer: 5.14V

Solution:

Total resistance R = 3Ω + 4Ω = 7Ω. Total current I = V/R = 12V / 7Ω = 1.71A. Voltage drop across 3Ω = I * R = 1.71A * 3Ω = 5.14V.

Using Kirchhoff's Voltage Law, if a loop has a 12V source and two resistors of 3

Practice Questions

Using Kirchhoff's Voltage Law, if a loop has a 12V source and two resistors of 3Ω and 4Ω, what is the voltage drop across the 3Ω resistor?

4.29V
5.14V
3.43V
6.0V

Questions & Step-by-Step Solutions

Using Kirchhoff's Voltage Law, if a loop has a 12V source and two resistors of 3Ω and 4Ω, what is the voltage drop across the 3Ω resistor?

Kirchhoff's Voltage Law – This law states that the sum of the electrical potential differences (voltage) around any closed network is zero.
Ohm's Law – This law relates voltage (V), current (I), and resistance (R) in a circuit, expressed as V = I * R.
Series Circuits – In a series circuit, the total resistance is the sum of individual resistances, and the same current flows through all components.

Using Kirchhoff's Voltage Law, if a loop has a 12V source and two resistors of 3

What’s inside this PDF?

Using Kirchhoff's Voltage Law, if a loop has a 12V source and two resistors of 3

Practice Questions

Questions & Step-by-Step Solutions

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