If a capacitor of 5 µF is charged to a voltage of 10V, what is the energy stored

₹0.0

Question: If a capacitor of 5 µF is charged to a voltage of 10V, what is the energy stored in the capacitor?

Options:

Correct Answer: 0.5 mJ

Solution:

Energy stored, U = 0.5 * C * V² = 0.5 * 5 x 10^-6 F * (10V)² = 0.25 mJ.

If a capacitor of 5 µF is charged to a voltage of 10V, what is the energy stored in the capacitor?

If a capacitor of 5 µF is charged to a voltage of 10V, what is the energy stored in the capacitor?

Step 1: Identify the values given in the problem. We have a capacitor with a capacitance (C) of 5 microfarads (µF) and a voltage (V) of 10 volts (V).
Step 2: Convert the capacitance from microfarads to farads. 5 µF is equal to 5 x 10^-6 F.
Step 3: Write down the formula for the energy (U) stored in a capacitor: U = 0.5 * C * V².
Step 4: Substitute the values into the formula. U = 0.5 * (5 x 10^-6 F) * (10 V)².
Step 5: Calculate (10 V)², which is 100 V².
Step 6: Now substitute this value back into the equation: U = 0.5 * (5 x 10^-6 F) * 100 V².
Step 7: Multiply 0.5 by 5 x 10^-6 F to get 2.5 x 10^-6 F.
Step 8: Now multiply 2.5 x 10^-6 F by 100 to get 0.00025 J.
Step 9: Convert joules to millijoules. 0.00025 J is equal to 0.25 mJ.

Capacitance and Energy Storage – The relationship between capacitance, voltage, and energy stored in a capacitor, given by the formula U = 0.5 * C * V².