If two capacitors of 4 µF and 6 µF are connected in parallel, what is the total

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Question: If two capacitors of 4 µF and 6 µF are connected in parallel, what is the total capacitance?

Options:

Correct Answer: 10 µF

Solution:

C_eq = C1 + C2 = 4 µF + 6 µF = 10 µF.

If two capacitors of 4 µF and 6 µF are connected in parallel, what is the total capacitance?

If two capacitors of 4 µF and 6 µF are connected in parallel, what is the total capacitance?

Step 1: Identify the values of the two capacitors. The first capacitor (C1) is 4 µF and the second capacitor (C2) is 6 µF.
Step 2: Understand that when capacitors are connected in parallel, you add their capacitances together.
Step 3: Write the formula for total capacitance in parallel: C_eq = C1 + C2.
Step 4: Substitute the values into the formula: C_eq = 4 µF + 6 µF.
Step 5: Perform the addition: 4 µF + 6 µF = 10 µF.
Step 6: Conclude that the total capacitance (C_eq) is 10 µF.

Capacitance in Parallel – When capacitors are connected in parallel, the total capacitance is the sum of the individual capacitances.