Question: What is the potential difference across a capacitor of 5 µF charged to 12 V?

Options:

1. 0.06 C
2. 0.06 J
3. 0.06 V
4. 0.06 F

Correct Answer: 0.06 J

Solution:

The energy stored in a capacitor is U = 0.5 * C * V^2 = 0.5 * 5 x 10^-6 F * (12 V)^2 = 0.36 J.