Question: What is the energy stored in a capacitor of 4 µF charged to a voltage of 12 V?
Options:
Correct Answer: 0.576 mJ
Solution:
Using the formula U = 1/2 * C * V^2 = 1/2 * 4 x 10^-6 F * (12 V)^2 = 0.288 mJ.