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In a series circuit with a 12 V battery and two resistors of 3 Ω and 6 Ω, what i

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Question: In a series circuit with a 12 V battery and two resistors of 3 Ω and 6 Ω, what is the current flowing through the circuit?

Options:

  1. 1 A
  2. 2 A
  3. 3 A
  4. 4 A

Correct Answer: 2 A

Solution: 

Total resistance R_total = R1 + R2 = 3 Ω + 6 Ω = 9 Ω. Current I = V/R_total = 12 V / 9 Ω = 1.33 A, approximately 1 A.

In a series circuit with a 12 V battery and two resistors of 3 Ω and 6 Ω, what i

Practice Questions

Q1
In a series circuit with a 12 V battery and two resistors of 3 Ω and 6 Ω, what is the current flowing through the circuit?
  1. 1 A
  2. 2 A
  3. 3 A
  4. 4 A

Questions & Step-by-Step Solutions

In a series circuit with a 12 V battery and two resistors of 3 Ω and 6 Ω, what is the current flowing through the circuit?
  • Ohm's Law – The relationship between voltage (V), current (I), and resistance (R) in an electrical circuit, expressed as V = I * R.
  • Series Circuit – A circuit configuration where components are connected end-to-end, resulting in the same current flowing through each component.
  • Total Resistance in Series – In a series circuit, the total resistance is the sum of the individual resistances.
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