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A train is moving at 90 km/h and a passenger inside walks towards the front of t

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Question: A train is moving at 90 km/h and a passenger inside walks towards the front of the train at 5 km/h. What is the passenger\'s speed relative to the ground?

Options:

  1. 85 km/h
  2. 90 km/h
  3. 95 km/h
  4. 5 km/h

Correct Answer: 95 km/h

Solution:

The passenger\'s speed relative to the ground is the speed of the train plus the speed of the passenger: 90 km/h + 5 km/h = 95 km/h.

A train is moving at 90 km/h and a passenger inside walks towards the front of t

Practice Questions

Q1
A train is moving at 90 km/h and a passenger inside walks towards the front of the train at 5 km/h. What is the passenger's speed relative to the ground?
  1. 85 km/h
  2. 90 km/h
  3. 95 km/h
  4. 5 km/h

Questions & Step-by-Step Solutions

A train is moving at 90 km/h and a passenger inside walks towards the front of the train at 5 km/h. What is the passenger's speed relative to the ground?
  • Step 1: Identify the speed of the train, which is 90 km/h.
  • Step 2: Identify the speed of the passenger walking towards the front of the train, which is 5 km/h.
  • Step 3: Since the passenger is walking in the same direction as the train, add the speed of the train and the speed of the passenger together.
  • Step 4: Calculate the total speed: 90 km/h (train) + 5 km/h (passenger) = 95 km/h.
  • Step 5: The result, 95 km/h, is the passenger's speed relative to the ground.
  • Relative Speed – Understanding how to calculate the speed of an object in relation to another moving object.
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