An object is thrown vertically upward with an initial velocity of 20 m/s. How hi

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Question: An object is thrown vertically upward with an initial velocity of 20 m/s. How high will it go before coming to a stop?

Options:

Correct Answer: 40 m

Solution:

Using the formula h = (v²)/(2g), where v = 20 m/s and g = 9.8 m/s², we get h = (20)²/(2 * 9.8) ≈ 20.4 m.

An object is thrown vertically upward with an initial velocity of 20 m/s. How high will it go before coming to a stop?

An object is thrown vertically upward with an initial velocity of 20 m/s. How high will it go before coming to a stop?

Step 1: Identify the initial velocity (v) of the object. In this case, v = 20 m/s.
Step 2: Identify the acceleration due to gravity (g). This is approximately g = 9.8 m/s².
Step 3: Use the formula to find the maximum height (h) the object will reach: h = (v²) / (2g).
Step 4: Calculate v², which is (20 m/s)² = 400 m²/s².
Step 5: Calculate 2g, which is 2 * 9.8 m/s² = 19.6 m/s².
Step 6: Divide v² by 2g to find h: h = 400 m²/s² / 19.6 m/s².
Step 7: Perform the division: h ≈ 20.4 m.

Kinematics – The study of motion, specifically how objects move under the influence of forces.
Energy Conservation – The principle that energy cannot be created or destroyed, only transformed from one form to another.
Projectile Motion – The motion of an object thrown into the air, subject to gravitational acceleration.