What is the change in entropy when 1 mole of an ideal gas expands isothermally f

Practice Questions

Q1
What is the change in entropy when 1 mole of an ideal gas expands isothermally from 10 L to 20 L at 300 K?
  1. 0.5 J/K
  2. 1.0 J/K
  3. 1.5 J/K
  4. 2.0 J/K

Questions & Step-by-Step Solutions

What is the change in entropy when 1 mole of an ideal gas expands isothermally from 10 L to 20 L at 300 K?
  • Step 1: Identify the variables needed for the calculation. We have 1 mole of gas (n = 1), the gas constant (R = 8.314 J/(mol·K)), the initial volume (Vi = 10 L), and the final volume (Vf = 20 L).
  • Step 2: Use the formula for change in entropy (ΔS) for an ideal gas during isothermal expansion: ΔS = nR ln(Vf/Vi).
  • Step 3: Substitute the values into the formula: ΔS = 1 * 8.314 * ln(20/10).
  • Step 4: Calculate the natural logarithm: ln(20/10) = ln(2).
  • Step 5: Calculate ln(2) which is approximately 0.693.
  • Step 6: Multiply the values: ΔS = 1 * 8.314 * 0.693.
  • Step 7: Perform the multiplication: ΔS ≈ 5.764 J/K.
  • Step 8: Round the result to one decimal place: ΔS ≈ 5.8 J/K.
No concepts available.
Soulshift Feedback ×

On a scale of 0–10, how likely are you to recommend The Soulshift Academy?

Not likely Very likely