What is the potential difference across a capacitor of 10 µF charged to 5 V?

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Question: What is the potential difference across a capacitor of 10 µF charged to 5 V?

Options:

Correct Answer: 0.1 J

Solution:

Energy stored in a capacitor U = 0.5 * C * V² = 0.5 * 10 x 10^-6 F * (5 V)² = 0.125 J.

What is the potential difference across a capacitor of 10 µF charged to 5 V?

What is the potential difference across a capacitor of 10 µF charged to 5 V?

Step 1: Identify the values given in the question. We have a capacitor with a capacitance (C) of 10 microfarads (µF) and a voltage (V) of 5 volts (V).
Step 2: Convert the capacitance from microfarads to farads. 10 µF is equal to 10 x 10^-6 F.
Step 3: Write down the formula for the energy stored in a capacitor: U = 0.5 * C * V².
Step 4: Substitute the values into the formula. Replace C with 10 x 10^-6 F and V with 5 V.
Step 5: Calculate V². 5 V squared is 25 V².
Step 6: Multiply the values: 0.5 * (10 x 10^-6 F) * 25 V².
Step 7: Calculate the result. 0.5 * 10 x 10^-6 * 25 = 0.125 J.

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