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What is the potential difference between two points in an electric field of 500

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Question: What is the potential difference between two points in an electric field of 500 N/C over a distance of 4 m?

Options:

  1. 2000 V
  2. 500 V
  3. 200 V
  4. 1000 V

Correct Answer: 1000 V

Solution: 

V = E * d = 500 N/C * 4 m = 2000 V.

What is the potential difference between two points in an electric field of 500

Practice Questions

Q1
What is the potential difference between two points in an electric field of 500 N/C over a distance of 4 m?
  1. 2000 V
  2. 500 V
  3. 200 V
  4. 1000 V

Questions & Step-by-Step Solutions

What is the potential difference between two points in an electric field of 500 N/C over a distance of 4 m?
  • Step 1: Identify the electric field strength (E), which is given as 500 N/C.
  • Step 2: Identify the distance (d) over which you want to find the potential difference, which is given as 4 m.
  • Step 3: Use the formula for potential difference (V), which is V = E * d.
  • Step 4: Substitute the values into the formula: V = 500 N/C * 4 m.
  • Step 5: Calculate the result: V = 2000 V.
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