In a series circuit with a 12V battery and two resistors of 4Ω and 6Ω, what is t

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Question: In a series circuit with a 12V battery and two resistors of 4Ω and 6Ω, what is the total current flowing through the circuit?

Options:

Correct Answer: 2A

Solution:

The total resistance in series is R_total = R1 + R2 = 4Ω + 6Ω = 10Ω. Using Ohm\'s law, I = V/R_total = 12V / 10Ω = 1.2A.

In a series circuit with a 12V battery and two resistors of 4Ω and 6Ω, what is the total current flowing through the circuit?

In a series circuit with a 12V battery and two resistors of 4Ω and 6Ω, what is the total current flowing through the circuit?

Step 1: Identify the voltage of the battery, which is 12V.
Step 2: Identify the resistors in the circuit, which are 4Ω and 6Ω.
Step 3: Calculate the total resistance in the series circuit by adding the resistances together: R_total = R1 + R2 = 4Ω + 6Ω.
Step 4: Perform the addition: R_total = 10Ω.
Step 5: Use Ohm's law to find the current: I = V / R_total.
Step 6: Substitute the values into the formula: I = 12V / 10Ω.
Step 7: Perform the division to find the current: I = 1.2A.

Series Circuit – In a series circuit, the total resistance is the sum of individual resistances, and the same current flows through all components.
Ohm's Law – Ohm's Law states that the current (I) through a conductor between two points is directly proportional to the voltage (V) across the two points and inversely proportional to the resistance (R).