In a series circuit with a 10 Ω and a 20 Ω resistor, what is the total resistanc

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Question: In a series circuit with a 10 Ω and a 20 Ω resistor, what is the total resistance?

Options:

Correct Answer: 30 Ω

Solution:

Total resistance in series is R_total = R1 + R2 = 10 Ω + 20 Ω = 30 Ω.

In a series circuit with a 10 Ω and a 20 Ω resistor, what is the total resistance?

In a series circuit with a 10 Ω and a 20 Ω resistor, what is the total resistance?

Step 1: Identify the resistors in the series circuit. We have two resistors: one is 10 Ω and the other is 20 Ω.
Step 2: Understand that in a series circuit, the total resistance is found by adding the resistance values of all the resistors together.
Step 3: Write down the formula for total resistance in a series circuit: R_total = R1 + R2.
Step 4: Substitute the values of the resistors into the formula: R_total = 10 Ω + 20 Ω.
Step 5: Perform the addition: 10 Ω + 20 Ω = 30 Ω.
Step 6: Conclude that the total resistance in the circuit is 30 Ω.

Series Circuit Resistance – In a series circuit, the total resistance is the sum of the individual resistances.