What is the electric potential energy stored in a capacitor with a capacitance o

What is the electric potential energy stored in a capacitor with a capacitance of 2 µF charged to 12 V?

What is the electric potential energy stored in a capacitor with a capacitance of 2 µF charged to 12 V?

Step 1: Identify the formula for electric potential energy stored in a capacitor, which is U = 1/2 C V^2.
Step 2: Identify the values given in the problem: capacitance (C) = 2 µF and voltage (V) = 12 V.
Step 3: Convert the capacitance from microfarads to farads. 2 µF = 2 x 10^-6 F.
Step 4: Substitute the values into the formula: U = 1/2 * (2 x 10^-6 F) * (12 V)^2.
Step 5: Calculate (12 V)^2, which is 144 V^2.
Step 6: Multiply 2 x 10^-6 F by 144 V^2 to get 2.88 x 10^-4 J.
Step 7: Multiply by 1/2 to find U: U = 1/2 * 2.88 x 10^-4 J = 1.44 x 10^-4 J.
Step 8: Convert joules to millijoules: 1.44 x 10^-4 J = 0.144 mJ.

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