What is the energy stored in a capacitor of 5µF charged to a voltage of 10V?

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Question: What is the energy stored in a capacitor of 5µF charged to a voltage of 10V?

Options:

Correct Answer: 0.5 mJ

Solution:

Energy (U) = 0.5 * C * V² = 0.5 * 5 x 10^-6 F * (10V)² = 0.25 mJ.

What is the energy stored in a capacitor of 5µF charged to a voltage of 10V?

What is the energy stored in a capacitor of 5µF charged to a voltage of 10V?

Step 1: Identify the formula for energy stored in a capacitor, which is U = 0.5 * C * V².
Step 2: Identify the values given: C (capacitance) = 5µF (microfarads) and V (voltage) = 10V.
Step 3: Convert the capacitance from microfarads to farads: 5µF = 5 x 10^-6 F.
Step 4: Substitute the values into the formula: U = 0.5 * (5 x 10^-6 F) * (10V)².
Step 5: Calculate (10V)², which is 100V².
Step 6: Multiply 0.5 * (5 x 10^-6 F) * 100V².
Step 7: Calculate the result: 0.5 * 5 * 100 x 10^-6 = 0.25 x 10^-3 = 0.25 mJ.

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