In a circuit with a 24V battery and two resistors in series (8Ω and 4Ω), what is

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Question: In a circuit with a 24V battery and two resistors in series (8Ω and 4Ω), what is the voltage drop across the 4Ω resistor?

Options:

Correct Answer: 6 V

Solution:

Total resistance = 8Ω + 4Ω = 12Ω. Current I = V/R = 24V / 12Ω = 2A. Voltage drop across 4Ω = I * R = 2A * 4Ω = 8 V.

In a circuit with a 24V battery and two resistors in series (8Ω and 4Ω), what is the voltage drop across the 4Ω resistor?

In a circuit with a 24V battery and two resistors in series (8Ω and 4Ω), what is the voltage drop across the 4Ω resistor?

Step 1: Identify the total resistance in the circuit by adding the resistances of the two resistors. Total resistance = 8Ω + 4Ω.
Step 2: Calculate the total resistance. Total resistance = 12Ω.
Step 3: Use Ohm's Law to find the current in the circuit. Current (I) = Voltage (V) / Total Resistance (R). Here, V = 24V and R = 12Ω.
Step 4: Calculate the current. I = 24V / 12Ω = 2A.
Step 5: To find the voltage drop across the 4Ω resistor, use the formula: Voltage drop = Current (I) * Resistance (R). Here, I = 2A and R = 4Ω.
Step 6: Calculate the voltage drop across the 4Ω resistor. Voltage drop = 2A * 4Ω = 8V.

Ohm's Law – The relationship between voltage (V), current (I), and resistance (R) in an electrical circuit, expressed as V = I * R.
Series Circuits – In a series circuit, the total resistance is the sum of individual resistances, and the same current flows through all components.
Voltage Division – In a series circuit, the voltage drop across a resistor can be calculated using the current flowing through it and its resistance.