If a capacitor of 5 µF is charged to a voltage of 10V, what is the stored energy

If a capacitor of 5 µF is charged to a voltage of 10V, what is the stored energy?

If a capacitor of 5 µF is charged to a voltage of 10V, what is the stored energy?

Step 1: Identify the values given in the problem. We have a capacitor with a capacitance (C) of 5 microfarads (µF) and a voltage (V) of 10 volts (V).
Step 2: Convert the capacitance from microfarads to farads. 5 µF is equal to 5 x 10^-6 F.
Step 3: Write down the formula for the energy stored in a capacitor: U = 0.5 * C * V².
Step 4: Substitute the values into the formula. U = 0.5 * (5 x 10^-6 F) * (10 V)².
Step 5: Calculate (10 V)², which is 100 V².
Step 6: Now substitute this value back into the equation: U = 0.5 * (5 x 10^-6 F) * 100 V².
Step 7: Multiply 0.5 by 5 x 10^-6 to get 2.5 x 10^-6.
Step 8: Now multiply 2.5 x 10^-6 by 100 to get 0.00025 joules.
Step 9: Convert joules to millijoules. 0.00025 joules is equal to 0.25 millijoules (mJ).

Capacitance and Energy Storage – Understanding how capacitors store energy based on their capacitance and the voltage applied.