If a capacitor of 10 µF is charged to a voltage of 5V, what is the stored energy

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Question: If a capacitor of 10 µF is charged to a voltage of 5V, what is the stored energy?

Options:

Correct Answer: 0.25 mJ

Solution:

Energy stored U = 0.5 * C * V^2 = 0.5 * 10 x 10^-6 F * (5V)^2 = 0.125 mJ.

If a capacitor of 10 µF is charged to a voltage of 5V, what is the stored energy?

If a capacitor of 10 µF is charged to a voltage of 5V, what is the stored energy?

Step 1: Identify the values given in the problem. We have a capacitor with a capacitance (C) of 10 microfarads (µF) and a voltage (V) of 5 volts (V).
Step 2: Convert the capacitance from microfarads to farads. 10 µF is equal to 10 x 10^-6 F.
Step 3: Write down the formula for the energy stored in a capacitor: U = 0.5 * C * V^2.
Step 4: Substitute the values into the formula. U = 0.5 * (10 x 10^-6 F) * (5 V)^2.
Step 5: Calculate (5 V)^2, which is 25 V^2.
Step 6: Now substitute this value back into the equation: U = 0.5 * (10 x 10^-6 F) * 25 V^2.
Step 7: Multiply 0.5 by 10 x 10^-6 F to get 5 x 10^-6 F.
Step 8: Now multiply 5 x 10^-6 F by 25 to get 125 x 10^-6 J.
Step 9: Convert 125 x 10^-6 J to millijoules (mJ). Since 1 J = 1000 mJ, we have 0.125 mJ.

Capacitor Energy Storage – The energy stored in a capacitor is calculated using the formula U = 0.5 * C * V^2, where U is the energy, C is the capacitance, and V is the voltage.