If a capacitor of 10 µF is charged to a voltage of 5V, what is the stored energy
Practice Questions
Q1
If a capacitor of 10 µF is charged to a voltage of 5V, what is the stored energy?
0.125 mJ
0.25 mJ
0.5 mJ
0.75 mJ
Questions & Step-by-Step Solutions
If a capacitor of 10 µF is charged to a voltage of 5V, what is the stored energy?
Step 1: Identify the values given in the problem. We have a capacitor with a capacitance (C) of 10 microfarads (µF) and a voltage (V) of 5 volts (V).
Step 2: Convert the capacitance from microfarads to farads. 10 µF is equal to 10 x 10^-6 F.
Step 3: Write down the formula for the energy stored in a capacitor: U = 0.5 * C * V^2.
Step 4: Substitute the values into the formula. U = 0.5 * (10 x 10^-6 F) * (5 V)^2.
Step 5: Calculate (5 V)^2, which is 25 V^2.
Step 6: Now substitute this value back into the equation: U = 0.5 * (10 x 10^-6 F) * 25 V^2.
Step 7: Multiply 0.5 by 10 x 10^-6 F to get 5 x 10^-6 F.
Step 8: Now multiply 5 x 10^-6 F by 25 to get 125 x 10^-6 J.
Step 9: Convert 125 x 10^-6 J to millijoules (mJ). Since 1 J = 1000 mJ, we have 0.125 mJ.
Capacitor Energy Storage – The energy stored in a capacitor is calculated using the formula U = 0.5 * C * V^2, where U is the energy, C is the capacitance, and V is the voltage.
