Using Kirchhoff's Voltage Law, what is the voltage drop across a 10Ω resistor if
Practice Questions
Q1
Using Kirchhoff's Voltage Law, what is the voltage drop across a 10Ω resistor if the total voltage in the loop is 20V and there is a 5Ω resistor in series?
10V
15V
5V
20V
Questions & Step-by-Step Solutions
Using Kirchhoff's Voltage Law, what is the voltage drop across a 10Ω resistor if the total voltage in the loop is 20V and there is a 5Ω resistor in series?
Step 1: Identify the total voltage in the loop, which is given as 20V.
Step 2: Identify the resistors in the series circuit: one is 10Ω (R1) and the other is 5Ω (R2).
Step 3: Calculate the total resistance in the circuit. Total resistance (R_total) = R1 + R2 = 10Ω + 5Ω = 15Ω.
Step 4: Use Ohm's Law (V = I * R) to find the current (I) in the circuit. Rearranging gives I = V_total / R_total = 20V / 15Ω.
Step 5: Calculate the current: I = 20V / 15Ω = 1.33 A (approximately).
Step 6: Now, calculate the voltage drop across the 10Ω resistor (V_R1) using Ohm's Law: V_R1 = I * R1 = 1.33 A * 10Ω.
