Using Kirchhoff's Voltage Law, what is the voltage drop across a 10Ω resistor if

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Question: Using Kirchhoff\'s Voltage Law, what is the voltage drop across a 10Ω resistor if the total voltage in the loop is 20V and there is a 5Ω resistor in series?

Options:

Correct Answer: 10V

Solution:

Using KVL, V_total = V_R1 + V_R2. V_R1 = 20V - (I * 5Ω). I = V/R = 20V / 15Ω = 1.33 A. V_R1 = 10Ω * 1.33 A = 13.33V.

Using Kirchhoff's Voltage Law, what is the voltage drop across a 10Ω resistor if

Practice Questions

Using Kirchhoff's Voltage Law, what is the voltage drop across a 10Ω resistor if the total voltage in the loop is 20V and there is a 5Ω resistor in series?

Questions & Step-by-Step Solutions

Using Kirchhoff's Voltage Law, what is the voltage drop across a 10Ω resistor if the total voltage in the loop is 20V and there is a 5Ω resistor in series?

Step 1: Identify the total voltage in the loop, which is given as 20V.
Step 2: Identify the resistors in the series circuit: one is 10Ω (R1) and the other is 5Ω (R2).
Step 3: Calculate the total resistance in the circuit. Total resistance (R_total) = R1 + R2 = 10Ω + 5Ω = 15Ω.
Step 4: Use Ohm's Law (V = I * R) to find the current (I) in the circuit. Rearranging gives I = V_total / R_total = 20V / 15Ω.
Step 5: Calculate the current: I = 20V / 15Ω = 1.33 A (approximately).
Step 6: Now, calculate the voltage drop across the 10Ω resistor (V_R1) using Ohm's Law: V_R1 = I * R1 = 1.33 A * 10Ω.
Step 7: Calculate V_R1: V_R1 = 1.33 A * 10Ω = 13.33V.

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Using Kirchhoff's Voltage Law, what is the voltage drop across a 10Ω resistor if

What’s inside this PDF?

Using Kirchhoff's Voltage Law, what is the voltage drop across a 10Ω resistor if

Practice Questions

Questions & Step-by-Step Solutions

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